Demonic God Posted May 20, 2019 Report Posted May 20, 2019 (edited) This is a mathematical problem, one that I devised some years ago, that I remembered recently. It might be of interest to those fond of mathematical challenges. The question is as follows: Find the sum of all numbers, such that, after 13 steps, which can be any of the following: Add 13 to the current number Subtract 13 to the current number Multiply the current number by 13 Divide the current number by 13 Raise the current number to the power of 13 Raise the current number to the power of -13 That the final number be of the same value of the original number Rewards: The most elegant solution submitted within one week's time will be rewarded with 1 GC All other correct answer will be rewarded with 3 SC Reward may increase if there's anyone willing to sponsor this quest Edited May 20, 2019 by fallen god words Quote
Demonic God Posted May 20, 2019 Author Report Posted May 20, 2019 (edited) This here is to acknowledge that Aia has solved this problem. I'd like to congratulate her for coming up with a solution in such short time. Edited May 20, 2019 by fallen god Aia del Mana and Sushi 2 Quote
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