[Md 3D]

But the images can already be viewed. The content that needs to be hidden would not made available for download until it is released.
We all already have the files downloaded by our browsers as it is, it is not exactly "hidden".

[Md 3D]

I fully support the client idea, however, it is far from an easy implementation.

I think there is a simpler approach, but one that yields the same advantages: a form of advanced caching.

Allow players to download the MD content (that which is readily available such as scene, creature, player, alliance etc, images) and store it on their computers, then give a field for them to specify where to load the files from. If new content is released, it will look it up in the stored vault and if not found, download it from the site.

Our browsers already do this caching, but not on such a permanant basis. Consider this: every scene takes at minimum 100kb to download, yes, I realise it doesn't sound like much but for someone with only 20mb to use it is plenty and multiply it by all players getting new content, but now instead of loading it from the site, it is loaded from the player's computer. You decrease load time for the player, save on bandwidth, and free up the server.

It wouldn't require recoding of the game, the same variables are passed to the pages but the content just gets found locally. Nothing new here, our browsers already cache websites.

[Game Icons Not Showing]

Have you checked that images are not disabled?

[Chewy Chewy In Da Slippers]

A worthy cause indeed. You have my vote.

[Heat Per Movement Doesnt Work...?]

I found that heat doesn't display well in Opera, have you tried using FireFox?
It can also happen that you lose the heat in the time it takes the page loads.

[Quest Rewards]

They do not reward enemies yet allow them to take part in their quests?

If it said "Complete this quest and the reward is this and this" it is in effect an agreement between the quest giver and taker that performing the quest would result in the reward.

Yes it is up to the RPC whether they will give the reward for the quest but without some guide line as to what would eliminate you from the reward anything could be argued.
For example, "Your post had an even number of letters thus you will not be rewarded".
Perhaps it was an implicit premise that the reward would not be given for being an enemy but it is unreasonable to deny a reward without even having placed a disclaimer that it could be denied (this is if they did not want to identify any conditions in particular, though this would also be rather unreasonable)
At the very least the possibility should have been identified.

Thus I see it as a breach of the quest agreement (from what I gather, there was nothing explicitly stated)

[quote name='BrightShield' date='05 July 2009 - 11:10 PM' timestamp='1246828259' post='36218']
Why would anyone do anyone's quest if not for the rewards and the recognition that one has accomplished them?
[/quote]

Sometimes it is the journey to complete the quest that is the reward, rather than what lies at the end

[Children]

Fenrir, I disagree. Children can be very useful when fighting, it just depends on how hard you throw them. You can also bludgeon the creature

[Riddle me this,]

@Eldrad

I must be missing the blatantly obvious but as far as far as I can see, my answer was the same as that of Sacosphilz, my alternating method of dealing coins is the same as his, could you explain to me where they differ?

[Riddle me this,]

Bah, I'm successfully out of time right now. I'll have to ponder it another time.

I'm not sure what you mean by

attempting to prove it, I would have thought the proof is that the pirates would not mutiny out of bloodlust because their 2 other proirities are then no longer fulfilled.

[Riddle me this,]

Hmmm

By "convincing them" I meant to prove his arguement.

By explaining that the pirates currently getting a coin will lose that coin if they mutiny (since it ultimately boils down to a single pirate getting the coin), they will by rational deduction see their only chance of both living and keeping their coin is to vote for the captain.

The reason he must deal the coins in an alternating manner is to ensure those pirates lose the coin by mutiny but keep it by supporting.

That's 2 pirate priorities fullfilled, overiding the third (bloodlust) and being rational, 2 out of 3 would be more convincing than 1 out of 3.

[Riddle me this,]

Continuation of Eldrad's Pirate Riddle:

Then the captain has to convince the crew they can't get any more money than what he gives them. All that needs to be understood is that to members who get a coin, will not get any more coins if they were to mutiny but WILL lose that coin.

I forgot that the captain himself is also a pirate and therefore functions under the same pirate priorities. That means he can only choose to take 51 coins because that is the most he can take while still staying alive.

If the crew should have a mutiny the replacement to the captain will do the same but take a coin more due to there being less pirates to divide between.

The crew would have a mutiny once again, yeilding the same result.

This would carry on until there are 2 pirates left and in that case the replacement captain takes all coins for himself and it becomes 1:1 again but the other pirate gets nothing.

Basically, all the pirates who ARE getting a coin must realise they will get nothing if they mutiny, to make sure this comes to pass, the captain must deal out coins in an alternating pattern starting by giving a coin to the lowest ranked pirate, skipping the pirate above him in rank, giving a coin to the next one, skipping the next one , etc.

This way he assures himself 49 other pirates' votes and gets the maximum plunder he can while staying alive.

Whew, I hope that make sense

PS My first riddle remains unsolved.

I know that Sacosphilz got it but he didn't actually post it.

[Riddle me this,]

@Metal Bunny's paragraph riddle

I'm not sure if this is the answer but there are no e's, the most common letter in the english alphabet and it is extremely verbose.

Riddle me this:

What has a voice, goes on four legs in the morning, on two legs in the afternoon, and on three legs in the evening?

[Riddle me this,]

@Eldrad's 100 Pirates Riddle

Let P = Total plunder (100 coins)

Let C = Captain's share of the plunder, where 0 < C <= 51.

Let D = P - C

Now, the captain chooses D pirates and gives them each 1 coin.

It all depends on how much plunder the captain chooses for himself, so at most, he will take 51 coins for himself and give 49 other pirates 1 coin. That way the attitude of the pirates would be 50:50 = 1:1 (including captain's vote)

and a mutiny would be avoided.

As for the analysis of the riddle, I assume that by "if it means they get the same amount of money they'd rather kill the captain just to see some blood" you do not mean that no two pirates may have the same share, otherwise you would need at minimum 4950 coins in order to give each one a different share.

[Riddle me this,]

@Sacosphilz

I know what you meant, I didn't think you didn't like it, I just thought I'd give you another

one to keep you busy.

As for your solution, it is the correct method by the wrong answer.

78 * 36 * 11 * 4 does not equal 30888.

Otherwise, with the correct follow through you got it.

[Riddle me this,]

Lol

What gets wetter the more it dries?

I see two possible answers:

1) A towel, by drying some it will get wetter.

or

2) A block of ice, by drying (getting hotter) it will melt and hence get wetter.

Sorry if I don't use the spoiler bar correctly, I'm new to this.

[Riddle me this,]

Perhaps this one will tickle your fancy more?

Also a simple riddle, this time more math orientated:

An ordinary deck of playing cards contains 52 cards divided into 4 suits, diamonds, hearts, clubs, spades.

Each suit contains 13 cards of the following denominations from smallest value to greatest:

2, 3, 4, 5, 6, 7, 8, 9, 10, J (jack), Q (queen), K (king), and A (ace).

The game of poker is played with an ordinary deck of playing cards in which a player will have a five-card hand.

There is a certain five-card holding called two pairs.

It contains 2 cards of one denomination, 2 cards of a second denomination, and a fifth card of a third denomination.

How many five-card poker hands contain two pairs?

If a five-card hand is dealt at random from an ordinary deck of playing cards, what is the probability that the hand contains two pairs?

[Riddle me this,]

Here is an easy one for now:

There are 3 boxes each with 2 marbles in them.

In one box there are 2 white marbles, in another there are 2 black marbles and in another there is one white and one black marble.

The boxes all have labels on them indicating what marbles they contain.

Somebody comes and rearranges the labels so that no box has the correct label anymore.

You are able to select one box and take one marble out.

How will you determine which label belongs to which box.

No, the boxes are not see-through etc, no trick just a simple riddle.