[quote name='Raven' timestamp='1329234585' post='104265']The numbers will be chosen from six throws of six dice. First number will determine in which place the number will be taken from in the next round. So if in first row we get number 2 then in second row we'll check the number which is on spot two and so on.
[i]For example:[/i]
[i]Raven throws 6 dice and gets [b]2[/b], 4, 5, 6, 4, 4 [/i]
[i]Raven throws 6 dice and gets 6, [b]5[/b], 4, 2, 3, 4 [/i]
[i]Raven throws 6 dice and gets 6, 6, 1, 2, [b]2[/b], 6 [/i]
[i]Raven throws 6 dice and gets 2, [b]4[/b], 5, 6, 4, 4 [/i]
[i]Raven throws 6 dice and gets 6, 5, 4, [b]2[/b], 3, 4 [/i]
[i]Raven throws 6 dice and gets 6, [b]6[/b], 1, 2, 2, 6 [/i]
Result: 2, 5, 2, 4, 6, 4, 2[/quote]
2, 5, 2, 4, 2, 6? No?
Also, you appear to have listed 7 numbers in your result...
LE: I fancied doing some math...
If you get 4 numbers correct, you get 20% of the total gained so far, you pick from 6 numbers for each dice throw, meaning the odds* are 1 in 6*6*6*6=1296 of getting it correct.
If you get 5 numbers correct, you get 40% of the total gained so far, you pick from 6 numbers for each dice throw, meaning the odds* are 1 in 6*6*6*6*6=7776 of getting it correct.
If you get all 6 numbers correct, you get 80% of the total gained so far, you pick from 6 numbers for each dice throw, meaning the odds* are 1 in 6*6*6*6*6*6=46656 of getting it correct.
Now ~personally~ I wouldn't even touch this unless if was closer to 3 rounds of dice to win, due to the frankly complete unlikelihood of anyone ever getting any coin back. Apart from you.
*Before anyone points out, yes I know these aren't entirely accurate as the number before picks the next dice number etc. but it then gets more complicated if I try and work that out.